Draxinar

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Draxinar
Draxinar.png
Draxinar, from Ultima VII Part Two
Species: dragon
Appearances
Ultima VII Part Two
Location: Serpent's Fang

Draxinar is a dragon encountered by the Avatar during the quest to the past in Ultima VII Part Two: The Silver Seed. Draxinar is a dragon of the green variety, and possibly the only non-ice dragon found in the game.

Description[edit]

Draxinar thought little of the Ophidians, feeling that they were narrow-minded and irrational after asking the Avatar if they were an envoy from Serpent's Fang. This also was why Draxinar held little interest in leaving his cave for the moment, finding the outside world way too dangerous right now due to the raging War of Imbalance, although he did feel the loneliness, his normal visitors usually only speaking through their swords before he killed them.

While none of his treasures were visible, Draxinar boasted with them, mentioning his aunt's son Longtooth. As it turned out, Longtooth had been quite a catch among female dragons and prime example of a dragon, until taking the challenge from a human warrior too lightly. Due to an ambush from the warrior's friends, Longtooth had to flee injured and since then was laughing stock, no longer being capable of his once great mental feats.

Draxinar was found inside the cave system which lead to Aram-Dol's Lair, but as the dragon revealed, neither he nor the arch-lich bother one another, although Draxinar held no love for Aram-Dol. He however warned, that Aram-Dol was very powerful with many followers, and how the lich did experiment on his prisoners to create the horrible Arachnians in order to secure his domain. Yet he also gave vivid description of the treasures that would wait if the lich is overcome.

Also known as "Stumpy", Draxinar had devised many riddles and would take great delight to quiz the Avatar on them, finding that this did help to not only get the time pass by, but also to sharpen his skill.

Riddle Answers[edit]

  • 1 of the monks lies (1)
  • 4 earrings are necessary (Worst case: 3 different + 1 to make a pair) (4)
  • He stumped nobody with his riddles! (0)
  • The answer is 14, but that's wrong. In the worst case, he takes 12, which makes 4 of each of the 3 designs. The 13th has to be the fifth to one of the designs, so 13 would be correct! (14)